Question

let R1 and R2 be the resistance of 10 ohm and 20 ohm connected in series with 8 volt battery find out the total current flowing in that circuit​

Answer 1

Answer:

The current flowing is 0.2 A.

Explanation:

Given :-

R₁ = 10 Ω

R₂ = 20 Ω

Series connection

Voltage (V) = 6 V

To find :-

Total current flowing (I)

Solution :-

Rₜ = R₁ + R₂

Rₜ = (10 + 20)Ω

∴ The total resistance is 30 Ω.

Now,

Ohm's law (V = IR)

Substituting we get,

I = V/R

I = 6/30

I = 0.2

∴ The current flowing is 0.2 A.

Answer 2

Answer:

let R1 and R2 be the resistance of 10 ohm and 20 ohm connected in series with 8 volt battery find out the total current flowing in that circuit​

Explanation:

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