Question

Let R1 R1 and R2 be the remainders on polynomial x cube + 2 x square - 5 x minus 7 and x cube + x square - 12 x + 6 are divided by X + 1 and x minus 2 respectively 3 8 1 + 8 is equal to 6 find the value of a

Answer 1

Answer:

Step-by-step explanation:2 square -5+7 cube_×2-12×+6 =381+8=6 ÷