Math, asked by puskie, 1 month ago

Let S denote the set of four-digit numbers made from the digits 0, 2, 3, 5, and 6, where the first digit cannot be zero.

a. How many numbers are there in S?

b. How many numbers in S have no repeated digit?

c. How many of those in part (b) are even?

d. How many of those in part (b) are greater than 4000?​

Answers

Answered by rishabhj031
0

Answer:

(a) option is correct so, you have go in this option

Answered by amitnrw
0

Given : S denote the set of four-digit numbers made from the digits 0, 2, 3, 5, and 6, where the first digit cannot be zero.

To Find :  a. How many numbers are there in S?

b. How many numbers in S have no repeated digit?

c. How many of those in part (b) are even?

d. How many of those in part (b) are greater than 4000?​

Solution:

0, 2, 3, 5, and 6

5 digits

Repeated digits

1st digit can be in  4 ways

all other digits can be in 5 ways

4 x 5 x 5 x 5   =  500

500 numbers are there in S

No repetition

1st digit can be in  4 ways

3 digits out of 4 can be selected in ⁴C₃ = 4 ways

remaining 3 digits can be in 3!

= 4 * 4 * 3!   = 96   numbers

96 numbers in S have no repeated digit

Even number in part b

ending with 0  - 1st 3 numbers can be in 4!  = 24

ending with 2  - 1st number in 3 ways  and remaining 3!  = 18

ending with 6  - 1st number in 3 ways and remaining 3!  =  18

18 + 18 + 24 = 60

60 numbers  are even when digits are not repeated

greater than 4000

starting with 5 or 6  - 2 ways

remaining 3 digits in 4 ! =  24 ways

2 * 24 = 48  numbers greater than 4000

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