Question

let's do the sum applying suitable Identity.
I) 101×99
.
.
please give me correct answer. solve full question .​

Answer 1

Answer:

9999

Step-by-step explanation:

   Method 1

101 × 99

= (100 + 1) (100 - 1)

= 100 × 100 + 100 × -1 + 1 × 100 + 1 × -1

= 10000 - 100 + 100 -1

= 9999

   Method 2

101 × 99

= (100 + 1) (100 - 1)

= 100² - 1²     ((a + b) (a - b) = a² - b²)

= 10000 - 1

= 9999

Hope that helps you...☺

Answer 2

Correct option is

A

9999

Given, 99×101=(100−1)(100+1).

We know, (a+b)(a−b)=a

2

−b

2

.

Then,

99×101=(100−1)(100+1)

=(100)

2

−1

2

=10000−1

=9999.

hope it help you