Question

Let's have some chemistry!!

Why does Al and Fe does not react with $\sf \: Conc. {H}_{2}{SO}_{4}$ ?

• Non-plagiarized(non-copied) answer= best answer​

Answer 1

Answer:

It is a weak acid

Explanation:

It is not ionised to a great extent

Answer 2

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CONCEPT : Reactivity of Elements

REACTIVITY SERIES :

• It is the series of metals, where metals are arranged in order of reactivity from highest to lowest.
• The elements are arranged as follow :

Potassium(K) > Sodium(Na) > Calcium(Ca) > Magnesium(Mg) > Aluminium(Al) > Carbon(C) > Zinc(Zn) > Iron(Fe) > Tin(Sn) > Lead(Pb) > Hydrogen(H) > Copper(Cu) > Silver(Ag) > Gold(Au) > Platinum(Pt)

• In the reactivity series, always a higher reactive metal can displace a lesser reactive metal in a chemical reaction. And such reactions are know as DISPLACEMENT REACTION.
• Where as, a lesser Reactive metal cannot displace a higher Reactive metal in any chemical reaction.

Comming to the question,

Why does Al and Fe does not react with $\sf \: Conc. {H}_{2}{SO}_{4}$ ?

• Actually both Fe and Al can react with $\sf \: Conc. {H}_{2}{SO}_{4}$ , hence , the statement is false.
• Well, as I said, the Reaction does occur in the following way :

$\boxed{ \sf \: {Fe} + \sf \: Conc. {H}_{2}{SO}_{4} \longmapsto \sf \: {({Fe}_{2}{SO}_{4})_{3}+ {SO}_{2} + {H}_{2}{0} }}$

$\boxed{ \sf \: {Al} + \sf \: Conc. {H}_{2}{SO}_{4} \longmapsto \sf \: {({Al}_{2}{SO}_{4})_{3}+ {SO}_{2} + {H}_{2}{0} }}$

• This is because, In the Reactivity series, both Fe (Iron) and Al (Aluminium) are placed above H (Hydrogen)
• Which means Fe (Iron) and Al (Aluminium) are more reactive metals than Hydrogen.
• Hence, Aluminium and Iron can displace Hydrogen in the compound $\sf \: Conc. {H}_{2}{SO}_{4}$ and form their respective products.

@SweetestBitter