Question

let's resolve into factors the following algebraic expression 192a^3+3​

Answer 1

Step-by-step explanation:

Solution:-

${192a}^{3} + 3 = 3(64 {a}^{3} + 1) \\ = 3((4 {a})^{3} + {1}^{3} ) \\ = 3((4a + 1)(16 {a}^{2} - 4a + 1)) \\ \\ the \: formula \: used \: here \: is \\ {x}^{3} + {y}^{3} = (x + y)( {x}^{2} - xy + {y}^{2} )$