Question

Let's see who can answer it

Answer 1

Let us assume that, ∠SPA = ∠APQ = a

Opposite angles of a parallelogram are equal.

Therefore,

⇒ ∠QRB = ∠SRB = a

Let ∠Q = ∠S = b

∠QBR = 180° - (a + b) [Angle sum property in ΔQBR]

∠PAS = 180° - (a + b) [Angle sum property in ΔPAS]

But a and 180° - (a + b) are alternate angles [Since PQ || RS]

⇒ a = 180° - (a + b)

⇒ ∠PAS = ∠SBY

∠PAS and ∠SRB are corresponding angles.

Hence, PA || BR

HENCE PROVED !!

MARK ME BRAINLIEST ^_^

Answer 2

Do it with the therom of parllel lines