let's see who is the brainliest
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Angle ABC = 90 (right angle)
TriAngle BDC = sum of angle BDC + DCB + DBC
DBC = half of angle ABC = 45
BDC = 90 (right angle)
DCB or ACB = X
Triangle BDC=90+X+45 = 180
X=180-135
X= 45
Since we can say that angle ABD = ACB
Vishalk:
It is there
where
Angle DCB = angle ACB
Are you understand
no
what answer you want
for what angle want to same
how dcb = acb makes abd = bdc
the angle of dcb = 45 the andle of acb = 45.
ok i edited answer
Answered by
11
Hii There!!!!
In ∆ ABD and ∆ACB,
angle BDA = angleBDC ( 90° each)
angle ABD = angle DBC ( BD perpendicular to AC and AC bisects angle B )
Angle A = angle A (common)
Therefore By AAA congurency criteria,
∆ ABD is congruent to ∆ ACB.
By CPCT , angle ABD = angle ACB.
______________________
Hope it helps☺
In ∆ ABD and ∆ACB,
angle BDA = angleBDC ( 90° each)
angle ABD = angle DBC ( BD perpendicular to AC and AC bisects angle B )
Angle A = angle A (common)
Therefore By AAA congurency criteria,
∆ ABD is congruent to ∆ ACB.
By CPCT , angle ABD = angle ACB.
______________________
Hope it helps☺
there is no criteria like AAA
it is angle angle angle criteria of congruency
it is used to prove 2 ∆'s as congruent
but the two triangles can have different lengths of its sides
although same angles
In this question concept of length is not applicable
how can AC bisect angle b
neither it can be bisected by it
because it is not given that ad = cd
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