Question

Let's see who will answer.

Sin inverse 3/5 + sin inverse 8/17 =cos inverse 36/85

Answer 1

$\textbf{check the attachment}$⬆⬆⬆


Be Brainly.


@karangrover12.

Answer 2

Hello Friend..❤️❤️

The answer of u r question is..✌️✌️



Given,

${sin}^{ - 1} \frac{3}{5} + {sin}^{ - 1} \frac{8}{17} = {cos}^{ - 1} \frac{36}{85}$


L.H.S


${sin}^{ - 1} ( \frac{3}{5} \sqrt{1 - \frac{64}{289} } + \frac{8}{17} \sqrt{1 - \frac{9}{25} } )$



${sin}^{ - 1} ( \frac{3}{5} \times \frac{15}{17} + \frac{8}{17} \times \frac{4}{5} )$




${sin}^{ - 1} ( \frac{45}{85} + \frac{32}{85} )$


${sin}^{ - 1} ( \frac{77}{85} )$

${sin}^{ - 1} \frac{77}{85} = \frac{8}{4}$



$using \: pythagoroas \: therom$

${b}^{2} = {h}^{2} - {b}^{2}$


${b}^{2} = 7225 - 5925$

$= 1296$


$b = 36$


${cos}^{ - 1} \frac{b}{h} = {cos}^{ - 1} \frac{36}{85} = rhs$


Thank you..⭐️⭐️⭐️