Question

let's try.....................​

Answer 1

Answer:

Hola ☘ ,

Explanation:

1)Both fluorine and oxygen have small size, high electronegativity and also high negative electron gain enthalpy.They can oxidise a metal to the highest oxidation states are shown in oxides and fluorides of transition metals.

2) Cr²+ . It can be explained on the basis of the standard electrode potential values E° (Cr²+/Cr³+ = -0.41V ) and E° (Fe²+/Fe³+ = +0.77V ) .Thus Cr²+ is easily oxidised to Cr³+ but Fe²+ cannot be readily oxidised to Fe³+

Hope it helps u dude .

Have a great day .

Answer 2

Answer:

hii bro ✌️

I know ki bahar nhi jaana hai isliye mumma Ghar par hi sweets Bana rhi hai and Maine toh pichle 6 mahine se Ghar ke bahar kadam bhi nhi rakha ❤️

by the way happy Raksha Bandhan in advance ❤️

kal Rakhi bhej dungi baandh Lena ❤️

byee ☺️