Let's write the value of(m2+n2) (m3+n3) by calculation if m+n=5 and MN=6
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Let's write the value of(m2+n2) (m3+n3) by calculation if m+n=5 and MN=6
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Here the given relation is, m+n=5 and mn=6
we have only the values of (m+n) and mn , so we have to express the given expression in the form of (m+n) and mn . Because of this, in case of (m2+n2) , we shall have to use the formula a2+b2=(a+b)2−2ab and in case of (m3+n3) ,we shall have to use the formula a3+b3=(a+b)3−3ab(a+b)
So now,
(m2+n2)(m3+n3)
= { (m+n)2−2mn } { (m+n)3−3mn(m+n) }
= { 52−(6×2) } { 53−(3×6×5) }
=(25−12)(125−90)
=(13×35)
=455
So, the value of { (m2+n2)(m3+n3) } is 455
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