let say a thief running on a train at 12 km /h. if the police car is moving with 80 km /h. if the speed of the train is 60 km /h then what is the speed of the thief with respect to the police car?
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Speed of the police car=80km/hr
Speed of train=60km/hr
Speed of thief on the train=12km/hr
Therefore,speed of the thief=60+12km/hr
=72km/hr
Hence,speed of the thief is less than the police car.
Speed of train=60km/hr
Speed of thief on the train=12km/hr
Therefore,speed of the thief=60+12km/hr
=72km/hr
Hence,speed of the thief is less than the police car.
jaya76:
It's my doubt. why can't the speed of the thief be 60 km/h because he is running on the train.
He is running on the train with 12km/hr so his speed will be 72km/hr.we have to add the speed ofthe train and the running speed of thief on the triain to calculate the total speed of the thief.
let him run but he is running on the train. train and he both in same direction. so he moves on the train which covers the distance
have u seen any movie in which any person is running on a train how he is moving forward because he is also running and running on the train makes his speed more ta the train if he continue to run then he will fall from the train.why?because his speed is more than the train.
so the one who is chasing him will need his+the train's speed to catch him.
OK thanks for your explanation
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3
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Speed of the police van,
v(p) = 30 km/h = 8.33 m/s
Muzzle speed of the bullet,
v(b) = 150 m/s
Speed of the thief’s car,
v(t )= 192 km/h = 53.33 m/s
Since the bullet is fired from a moving van, its resultant speed can be obtained as: = 150 + 8.33 = 158.33 m/s
Since both the vehicles are moving in the same direction, the velocity with which the bullet hits the thief’s car can be obtained as: v(bt) = v(b) – v(t)= 158.33 – 53.33 = 105 m/s
I hope, this will help you
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