Question

Let set A be a set having first 50 perfect squares and set B be a set having first 20 positive numbers which have three factors.
Then sum of all elements in set (B-A) is?​

Answer 1

Answer:

Input : a = 3, b = 8

Output : 1

The only perfect in given range is 4.

Input : a = 9, b = 25

Output : 3

The three squares in given range are 9,

16 and 25

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Answer 2

Answer:

Step-by-step explanation:

Set A = (1, 4, 9, 16………..2500)

Set B = Square of prime numbers(because square of any prime number will have 3 factors)

(4, 9, 25, 49, 121, 169, 289, 361, 529, 841…5041)

Required sum

= 2809 + 3481 + 3721 + 4489 + 5041 = 19541.