Question

Let t =0

1+t=A(2+3t)+B(3+t)

Answer 1

Step-by-step explanation:

Given that t= 0

then,

1+t=A(2+3(0))+B(3+0)

=A(2+3)+B(3)

=A(5)+B(3)

Answer 2

Answer:

A=1/5,B=1/5

Step-by-step explanation:

for t=0

we have,

A(2+3(0)) + B(3+(0)) = 1

A(2) + B(3) = 1

2A + 3B = 1

for t=1

we have,

A(2+3(1)) + B(3+(1)) = 1 + 1

A(5) + B(4) = 2

5A + 4B = 2

solving equations 1 and 2,

we get

A=B; A=1/5; B=1/5