Question

Let T be the set of integers {3,11,19,27....451,459,467} and S be a subset of T such that the sum of no two
elements of S is 470. The maximum possible number of elements in S is
a) 32
b) 28
c) 29
d) 30
​

Answer 1

Answer:

HI,

Step-by-step explanation:

Answer 2

Answer:

30

Step-by-step explanation:

Now, as we know,

the formula to find nth term of an AP series

a+(n-1)d=Tn

a=3

d=8

nth term = 467

no. of terms(n) = ?

467=3+(n-1)8

n=472/8

n=59

there is total 59 elements

59/2=29.5 pairs

approximatly 30 pairs

that equal to 30 elements

#SPJ3