Math, asked by gss83638, 1 month ago

Let T be the triangle formed by the straight line 3x + 5y - 45 = 0 and the coordinate axes. Let the circumcircle of T have radius of length L, measured in the same unit as the coordinate axes. Then, the integer closest to L is​

Answers

Answered by nanub
1

We know that the equation of the straight line is 3x + 5y = 45

 \frac{x}{15}  +  \frac{y}{9}  = 1 \\

The intercepts are (15,0) and (0,9) respectively

Since it's a right-angled triangle, we know that Circumradius (R) =

 \frac{hypotenuse}{2}

Circumradius =

 \frac{ \sqrt{ {9}^{2}  +  {15}^{2} } }{2}  =  \frac{3}{2}  \times  \sqrt{34}

We know that square root of 34 is approximately equal to 6

So, from trial and error to find the closest number, we find that the value of Circumradius is very close to 9

So, the integer closest to L = 9

Answer

9

Answered by sonprodigal
2

Answer:

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