Math, asked by Rickonix9903, 1 year ago

Let f:A\rightarrow \Pi _{\alpha \epsilon J} X_{\alpha} be given by the equation f(a)=(f_{\alpha} (a))_{\alpha \epsilon J} , where f_{\alpha} :A \rightarrow X_{\alpha} for each\alpha. Let \Pi_{\alpha \epsilon J} X_{\alpha} have the product topology. Then show that the function f is continuous if and only if each function f_{\alpha} is continuous.

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Answered by ssvijay738
0

Let f:A\rightarrow \Pi _{\alpha \epsilon J} X_{\alpha} be given by the equation f(a)=(f_{\alpha} (a))_{\alpha \epsilon J} , where f_{\alpha} :A \rightarrow X_{\alpha} for each\alpha. Let \Pi_{\alpha \epsilon J} X_{\alpha} have the product topology. Then show that the function f is continuous if and only if each function f_{\alpha} is continuous.

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