Question

Let the four numbers be (a-3d), (a-d), (a+d) & (a+3d).




Now According to question

Their sum :

(a-3d)+(a-d)+(a+d)+(a+3d)=28
4a = 28
a=7.

2.Their product
(a-3d)²+(a-d)²+(a+d)²+(a+3d)²=216
4a²+20d²=216
a² +hting the value of a
49 + 5d² = 54
5d² = 5
d² = 1​

Answer 1

Answer:

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Answer 2

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