Let the function f:R⇒R be defined by f(x)=x²,
find:
i:f^-1,
ii:f^-1(-4)
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Answer:
Explanation:
Hey mate here is your answer:
→f : R⇒R and defined by f(x)=x²,
→ i: f^-1 ⇒ {-2,2}.
→ ii: f^-1(-4)⇒√-4(not a real number ∴ there is no element in the domain which can map to -4).
Hope it helps you dear//
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