Let the HCF of 210 and 55 be expressed as 210 ×5 +55k find k
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hcf of 210 and 55=5
5=210*55+55k
5=11550+55k
55k=11550-5
55k=11545
k=11545/55
k=209.9
5=210*55+55k
5=11550+55k
55k=11550-5
55k=11545
k=11545/55
k=209.9
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