Question

let the probability of patients recovering from disorder after treatment is 0.75. suppose there are 4 patients . x denotes number of patients recovered. probability of P(X=0)

Answer 1

Answer:

0.25 or 25 % is the right answer

Answer 2

The probability of P(x=0) is 0.0351

Given : The probability of patients recovering from disorder after treatment is 0.75

Total number of patients 4

Number of patients recovered x

To Find : The probability P(x=0)

Solution : The probability of P(x=0) is 0.0351

The probability of patients recovering from disorder after treatment is 0.75 which is equal to $\frac{3}{4}$

Probability that the person will not recover from the disorder is (q) is

1-p

= $1-\frac{3}{4}$

= $\frac{1}{4}$

Number of patients is (n) = 4

We have to find probability of P at x = 0

So using the formula

$P(x) = n_{C_{x} } p^{x}q^{n-x}$

Now putting the values of n = 4 , p = $\frac{3}{4}$ q = $\frac{1}{4}$ and x = 0 in the above equation we get

$P(0) = 4_{C}_{0}(\frac{3}{4}) ^{2} (\frac{1}{4} )^{2}$

= $\frac{9}{16}$ ×$\frac{1}{16}$

= $\frac{9}{256}$

=0.0351

So the probability of P(x=0) is 0.0351

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