Question

let the resistance of an electrical component remains constant while the potential difference across two ends of the conductor decreses to half of its former value what change will occur in the current through it

Answer 1

By Ohm's law
V=IR
R remains constant so,
R=V/I
V gets halved
V→V/2
But R remains constant
so
R=(V/2)/x                    (x is the new current)
x=V/2R
I=V/R
substitute I in x equation
x=I/2
So when potential gets halved, current also gets halved.

Answer 2

The amount of current flowing through the electrical component is reduced by half.

Explanation:

According to Ohm’s law

V = IR

where

V= potential difference

I= Current

R = Resistance

By modifying the equation

I=V/R ——- (i)

potential difference across the two ends of the component decreases to half

therefore, the new potential difference be Vʹ=V/2

Resistance remains constant across the electrical component

new current is drawn by the electrical component is Iʹ = Vʹ/R

= (V/2)/R        {Substituting Vʹ=V/2 in the above equation}

= (1/2) (V/R)

= (1/2) I = I/2

Hence the amount of current flowing through the electrical component is reduced by half.

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