let the resistance of an electrical component remains constant while the potential difference across two ends of the conductor decreses to half of its former value what change will occur in the current through it
Answers
Answered by
593
By Ohm's law
V=IR
R remains constant so,
R=V/I
V gets halved
V→V/2
But R remains constant
so
R=(V/2)/x (x is the new current)
x=V/2R
I=V/R
substitute I in x equation
x=I/2
So when potential gets halved, current also gets halved.
V=IR
R remains constant so,
R=V/I
V gets halved
V→V/2
But R remains constant
so
R=(V/2)/x (x is the new current)
x=V/2R
I=V/R
substitute I in x equation
x=I/2
So when potential gets halved, current also gets halved.
Anonymous:
ok
Answered by
87
The amount of current flowing through the electrical component is reduced by half.
Explanation:
According to Ohm’s law
V = IR
where
V= potential difference
I= Current
R = Resistance
By modifying the equation
I=V/R ——- (i)
potential difference across the two ends of the component decreases to half
therefore, the new potential difference be Vʹ=V/2
Resistance remains constant across the electrical component
new current is drawn by the electrical component is Iʹ = Vʹ/R
= (V/2)/R {Substituting Vʹ=V/2 in the above equation}
= (1/2) (V/R)
= (1/2) I = I/2
Hence the amount of current flowing through the electrical component is reduced by half.
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