Let the three number are x-1,x+2,x-7 are in AP.Find the value of x.
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If 3 numbers are in AP, then their common difference is same.
Therefore,
2b = a + c ; where a = x - 1, b = x + 2 and c = x - 7
Putting the values
2 ( x + 2 ) = x - 1 + x - 7
2 x + 4 = 2x - 8.
I have tried it.
But i think you had written the question wrong or changed the pattern of series.
It is not further possible.
Okay
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Therefore,
2b = a + c ; where a = x - 1, b = x + 2 and c = x - 7
Putting the values
2 ( x + 2 ) = x - 1 + x - 7
2 x + 4 = 2x - 8.
I have tried it.
But i think you had written the question wrong or changed the pattern of series.
It is not further possible.
Okay
Mark me brainliest
And for further answering follow me
Have a great day
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