Math, asked by LibinD, 1 year ago

Let to help me please....

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Answered by siddhartharao77
7
Given LHS = sinA(1 + tan A) + cosA(1 + cot A)

 = sinA + sinA * tan A + cosA +  cosA * cotA

sin A + sinA *  \frac{sinA}{cosA} + cos A + cosA *  \frac{cosA}{sinA}

sinA +  \frac{sin^2A}{cosA}  + cosA +  \frac{cos^2A}{sinA}

sinA +  \frac{cos^2A}{sinA} + cosA +  \frac{sin^2A}{cosA}

 \frac{sin^2A + cos^2A}{sinA} +  \frac{cos^2A + sin^2A}{cosA}

 \frac{1}{sinA} +  \frac{1}{cosA}

= cosecA + secA.


LHS = RHS.


Hope this helps!

siddhartharao77: :-))
amber3: thanks
amber3: sinA+sinA kaisay aya
siddhartharao77: Which step?
amber3: second
siddhartharao77: Its multiplication bro.sinA(1 + tanA) = sinA * 1 + sinA * tanA = sinA + sinA * tanA
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