Question

Let triangle ABC is congruent to triangle DEF and their areas be 100 cm² and 49 cm2. If EF = 8.4cm find BC​ 'pls answer fast it is urgent If anyone answers I mark it as brainest answer'​

Answer 1

Answer:

Heyy mate ❤✌✌❤

Here's your Answer...

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Ar(ABC)/Ar(DEF) = 64/ 121 --------(1)

As we know that, The Ratio of Similar triangle is equal to the square of the ratio pf yheir side.

=> AB/EF = (X/ 15.4)^2 -------(2)

FROM EQUATION 1 AND 2.

=> 64/121 = (X/15.4)^2

=> 8/ 11= X / 15.4

=> X = 15.4 × 8/11

=> x = 11.2cm✔✔

Answer 2

Answer:

Ar(ABC)/Ar(DEF) = 64/ 121 --------(1)

As we know that, The Ratio of Similar triangle is equal to the square of the ratio pf yheir side.

=> AB/EF = (X/ 15.4)^2 -------(2)

FROM EQUATION 1 AND 2.

=> 64/121 = (X/15.4)^2

=> 8/ 11= X / 15.4

=> X = 15.4 x 8/11

$\huge\mathcal{\fbox{\fbox{\pink{x= 11.2cm}}}}$