Let U= {1, 2, 3, 4,5, 6, 7, 8, 9}, A = {1, 2, 3, 4}, B= {2, 4, 6, 8} and C={3, 4, 5, 6} Find
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we know, complement of set , A' = U - A
so, (A' )' = (U - A)' = U - (U - A) = U - U + A = A
hence, ( A ') ' = A
[complement of set C means set of that elements that do not belong to C. ]
here given,
U = {1, 2, 3, 4, 5, 6, 7, 8, 9}
A = {1, 2, 3, 4}
so, (A')' = A = {1, 2, 3, 4}
so, (A' )' = (U - A)' = U - (U - A) = U - U + A = A
hence, ( A ') ' = A
[complement of set C means set of that elements that do not belong to C. ]
here given,
U = {1, 2, 3, 4, 5, 6, 7, 8, 9}
A = {1, 2, 3, 4}
so, (A')' = A = {1, 2, 3, 4}
Answered by
0
Solution :
Given U = { 1,2,3,4,5,6,7,8,9 }
A = { 1,2,3,4 } ,
B = { 2,4,6,8 },
C = { 3,4,5,6 }
*************************************
A' ={x:x€U and x doesn't belongs to A}
**************************************
i ) A' = U - A
= { 1,2,3,4,5,6,7,8,9 } - { 1,2,3,4 }
= { 5,6,7,8,9 }
ii ) ( A' )' = U - A'
= { 1,2,3,4,5,6,7,8,9 } - { 5,6,7,8,9 }
= { 1,2,3,4 }
= A
Therefore ,
( A' )' = A
••••••
Given U = { 1,2,3,4,5,6,7,8,9 }
A = { 1,2,3,4 } ,
B = { 2,4,6,8 },
C = { 3,4,5,6 }
*************************************
A' ={x:x€U and x doesn't belongs to A}
**************************************
i ) A' = U - A
= { 1,2,3,4,5,6,7,8,9 } - { 1,2,3,4 }
= { 5,6,7,8,9 }
ii ) ( A' )' = U - A'
= { 1,2,3,4,5,6,7,8,9 } - { 5,6,7,8,9 }
= { 1,2,3,4 }
= A
Therefore ,
( A' )' = A
••••••
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