Question

let us consider a uniform electric field 2i-8j+2k newton per coulamb what is the flux through a circle of area 5m square lying on x z plane​

Answer 1

Question :

let us consider a uniform electric field $\tt 2\hat{i}-8\hat{j}+2\hat{k}$ newton per coulamb what is the flux through a circle of area 5m square lying on x-z plane.

Given :

$\tt \vec{E} = 2\hat{i}-8\hat{j}+2\hat{k}$

$\tt \vec{A} = 5\hat{j} \: {m}^{2}$

To Find :

Flux ($\tt \phi$ )= ?

Formula :

$\tt \phi = \vec{E}.\vec{A}$

Where ,

$\tt \phi$ : Flux

$\tt \vec{E}$ : Electric Field

$\tt \vec{A}$ : Area

Solution :

$\tt \phi = \bar{E}.\bar{A}$

$\tt \implies \phi = (2\hat{i}-8\hat{j}+2\hat{k})(5\hat{j})$

$\tt \implies \phi = -8 × 5$

$\tt \implies \phi = -40$

So flux is 40 units.