Let us consider the formula F=mv2/r. Check whether this formula is dimensionally correct. Also consider the velocity of a particle varies with time according to the relation v=At2+B t +CF in which v is the velocity, t is the time and F is the Force. Hence evaluate the dimensions and units of A,B and C.
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Hey Buddy here's ur answer
Given
F=mV²/r
Dimensional Formula of Force= mx a
=mxv/t
L.H.S=F =M¹L¹T⁻²---------(1)
R.H.S=mv²/r
=M¹(L¹T⁻¹)²/L
=M¹L²T⁻²/L
=M¹L¹T⁻²------------(2)
By equation 1 and 2
L.H.S =R.H.S
Since the dimensions of F and mV²/r are equal... so equation is dimensionally correct.
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AnswF= mv^2/r
Explanation:
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