train A leaves station X at 5 am and rech station Y at 9 am .another train B leaves Y at 6.30 am and reach station X at 10 am .at whatbtime do the two train meet ?
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Answer:
Hey dear here is ur answer.
Time taken by train 1 from x to y = 4 hours
It travels for 2 hours before train 2 starts.
Time taken by train 2 from y to x = 3.5 hours
Let distance between x & y = LCM(4,3.5) = 28 kms
Speed of Train 1 = 28/4 = 7 kmph
Speed of Train 2 = 28/3.5 = 8 kmph
Train 1 covers 7 x 2 = 14 km by the time Train 2 starts at 7 AM.
So, distance between the two trains at 7 AM is 28 - 14 = 14km
Relative speed = 7 + 8 = 15 kmph
Time taken to cross each other = 14/15 hours or 56 minutes.
=> They meet at 7:56 AM.
Hope it helps.
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