Question

Let vector a = 2i - j + 2k and vector b = i+2j-k. Let a vector v be in the plane containing vector a and vector b. If vector v is perpendicular to the vector 3i +2j-k and its projection on vector a is 19 units, then |2v|² is equal​

Answer 1

Step-by-step explanation:

Write antonyms of the following words

Above

Certain

Failure

Loose

Knit

Fame

Callous

Bright

Defend

Attract

Decrease

Civil

please answer me this...

Answer 2

Answer:

1494 i think

Step-by-step explanation:

let a=2i-j+2k  b=i+2j-k and 3i+2j-k=c

if v is in plane of a and b then v=Xa+Yb

if v is peripendicular to c then v.c=0

so v=αc×(a×b)

v=α[c×(a×b)] ⇒α[(c.b)a-(c.a)b]

on solving we get  v= α[14i-12j+18k]

we know that v.a{cap}=19

so α[14i-12j+18k ]. (2i-j+2k)/ mod 2i-j+2k=19

sorry i am not able to use symbols but please understand

α[14i-12j+18k].[2i-j+2k]/3 = 19

α=4/3

now substitute α in v=α[14i-12j+18k]

mod of 2v square=1494 will be the answer