Math, asked by av60464, 1 month ago

Let x and y be the 2 real numbers satisfying y= (2008x +2009/2010x-2011)^1/2 + (2008x+2009/2011-2010x)^1/2 ​

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Answers

Answered by pulakmath007
4

SOLUTION

TO DETERMINE

Let x and y be the 2 real numbers satisfying

 \displaystyle \sf{y =  \sqrt{ \frac{2008x + 2009}{2010x - 2011}  } + \sqrt{ \frac{2008x + 2009}{2011 - 2010x } } }

EVALUATION

Here it is given that

 \displaystyle \sf{y =  \sqrt{ \frac{2008x + 2009}{2010x - 2011}  } + \sqrt{ \frac{2008x + 2009}{2011 - 2010x } } }

Let us assume that

 \displaystyle \sf{a  = \frac{2008x + 2009}{2010x - 2011}  }

Then above becomes

 \displaystyle \sf{y =  \sqrt{ a} + \sqrt{  - a } }

Since y is a real number

Thus we get

 \displaystyle \sf{ a  \geqslant 0 \:  \: and \:  \:   - a \leqslant 0  }

Which gives a = 0

Consequently we get y = 0

FINAL ANSWER

Hence the required value of y = 0

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