Question

Let x be the class mark and y be the upper limit of a class-interval in a continuous frequency distribution .
The lower limit of the class is:

Answer 1

Answer:

y-x

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Answer 2

Answer:

The first one is wrong, the correct answer is 2x-y

Step-by-step explanation:

Let lower limit = a

We know that,

Class mark = (lower limit+upper limit)/2

So,

x=(a+y)/2

2x=a+y

a=2x-y

Lower limit is 2x-y