Let x be the least number, which when divided by 5, 6, 7 and 8 leaves a remainder 3 in each case but when divided by 9 leaves no remainder. the sum of digits of x is
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HCF and LCM #5
What is the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder? Hence the number can be written in the form (840k + 3) which is divisible by 9. If k = 1, number = (840 × 1) + 3 = 843 which is not divisible by 9.
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