Question

Let X be the set consisting of the first 2018 terms of the arithmetic progression 1, 6, 11, ….. , and Y be the
set consisting of the first 2018 terms of arithmetic progression 9, 16, 23, ….. . Then, the number of
elements in the set X ∪ Y is

Answer 1

Answer:

answer is 3748

Step-by-step explanation:

X:1,6,11,_________, 10086

Y:9,16,23,________, 14128

X∩Y :16,51,86, _________

Let m=n(X∩Y)

∴16+(m−1)×35≤10086

⇒m≤288.71

⇒m=288

∴n(X∪Y)=n(X)+n(Y)−n(X∩Y)

=2018+2018−288=3748.

Answer 2

Answer:

344 strutt and why not received an environment