Chemistry, asked by dmshivakumar4067, 10 months ago

Match the thermodynamic processes given under Column I with the expression given under Column II:
Column I Column II
(A) Freezing of water at 273 K and 1 atm (P) q = 0
(B) Expansion of 1 mol of an ideal gas into a (Q) w = 0
vacuum under isolated conditions
(C) Mixing of equal volumes of two ideal gases (R) ????S????y???? < 0
at constant temperature and pressure in an
isolated container
(D) Reversible heating of H2(g) at 1 atm from (S) ????U = 0
300 K to 600 K, followed by reversible (T) ????G = 0
cooling to 300 K at 1 atm

Answers

Answered by aprajitakumari85799
0

Explanation:

`rarr` r, t; B `rarr` p, q, s; C `rarr` p, q, s ; D `rarr` p, q, s, t

Solution :

`H_(2)O(l)rarrH_(2)O(s)" at 273 K. & 1 atm"` <br> `DeltaH=-ve=q` <br> `DeltaS_(sys)lt0, DeltaG=0` <br> `wne0` (as water expands on freezing), `DeltaUne0` <br> (B) Free expansion of ideal gas q=0 <br> w=0 <br> `DeltaU=0` <br> `DeltaS_(sys)gt0` <br> `DeltaGlt0` <br> (C ) Mixing of equal volume of ideal gases at constant pressure & temp in an isolated container <br> `q=0, w=0, DeltaU=0, DeltaS_(sys)gt0, DeltaGlt0` <br> (D) `H_(2)(g)300 K underset("Heating, 1 atm")overset("Reversible")rarr600 K underset("Cooling, 1 atm")overset("Reversible")rarr300 K` <br> `q=0, w=0, DeltaU=0, DeltaG=0, DeltaS_(sys)=0`

Answered by pramodtripathi807
0

Answer:

t I have to be a good day today I have no clue how much is it a lot of

Similar questions