Question

Let x,y and z be real number such that x+y+z=20 and x+2y+3z=16,then the value of x+3y+5z is-

Answer 1

Answer:

The correct answer is 12 . see the explanation .

Step-by-step explanation:

x + y + z = 20 - ( 1 )

x + 2y + 3z = 16 - ( 2 )

subtract (1) and (2)

y + 2z = - 4

substitute these values in x + 3y +5z = (x + 2y + 3z) +( y + 2z)

hence, x + 3y +5z = 16 - 4 = 12