Math, asked by Anonymous, 7 months ago

Let x11,x21,....,xn1 (xi=0 for i=1,2,...,n) be in A.P. such that x1=4 and x21=20. If n is the least positive integer for which xn>50, then i=1∑n(xi1) is equal

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Answered by shejisuresh2

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siwwisss

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Answered by rosey25

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$<!DOCTYPE html> <html> <svg width="100%" height="300px">\ \textless \ br /\ \textgreater \ <g id="R1" transform="translate(250 250)"> \ \textless \ br /\ \textgreater \ <ellipse rx="100" ry="0" opacity=".3">\ \textless \ br /\ \textgreater \ <animateTransform attributeName="transform" type="rotate" dur="7s" from="0" to="360" repeatCount="indefinite" />\ \textless \ br /\ \textgreater \ <animate attributeName="cx" dur="8s" values="-20; 220; -20" repeatCount="indefinite" />\ \textless \ br /\ \textgreater \ <animate attributeName="ry" dur="3s" values="10; 60; 10" repeatCount="indefinite" />\ \textless \ br /\ \textgreater \ </ellipse>\ \textless \ br /\ \textgreater \ </g><use xlink:href="#R1" transform="rotate(72 390 150)" />\ \textless \ br /\ \textgreater \ <use xlink:href="#R1" transform="rotate(144 390 150)" />\ \textless \ br /\ \textgreater \ <use xlink:href="#R1" transform="rotate(216 390 150)" />\ \textless \ br /\ \textgreater \ <use xlink:href="#R1" transform="rotate(288 390 150)" />\ \textless \ br /\ \textgreater \ </svg></body></html >$

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Let x1​1​,x2​1​,....,xn​1​ (xi​​=0 for i=1,2,...,n) be in A.P. such that x1​=4 and x21​=20. If n is the least positive integer for which xn​>50, then i=1∑n​(xi​1​) is equal ​

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Let x11,x21,....,xn1 (xi=0 for i=1,2,...,n) be in A.P. such that x1=4 and x21=20. If n is the least positive integer for which xn>50, then i=1∑n(xi1) is equal