let y =sin³x then find dy÷dx
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Answered by
6
3sin square x. llllllllllllllllll
sunil223:
derivative of y = sin cube x
Answered by
44
Applying chain rule
y=sin³x
dy/dx = d/dx (sin³x).d/dx (sinx)
= 3sin^3-1 x . (cosx)
= 3sin²xcosx
y=sin³x
dy/dx = d/dx (sin³x).d/dx (sinx)
= 3sin^3-1 x . (cosx)
= 3sin²xcosx
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