Question

the diagonal of a rectangular field is 60 metres more than the shorter side if the longer side is 30 metre more than the shorter side find the sides of the field

Answer 1

l=120, b=90, h= 150 are the answers

Answer 2

Answer:-

Consider that:-

→ The shorter side of the rectangle is x m.

→ Then, larger side of the rectangle = (x + 30) m

→ Diagonal of the rectangle = √[x²+ (x + 30)²]

Given:-

→ The length of the diagonal is = x + 30 m.

Therefore,

→ √[x² + (x + 30)²] = x + 60

Squaring on both the sides, we get;

→ x² + (x + 30)² = (x + 60)²

→ x² + x² + 900 + 60x = x² + 3600 + 120x

→ x² – 60x – 2700 = 0

→ x² – 90x + 30x – 2700 = 0

→ x(x – 90) + 30(x -90)

→ (x – 90)(x + 30) = 0

→ x = 90, -30