let y varies directly as x. If y=12when x=4 ,then write a linear equation . what is the value of y when x = 5?
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When y varies directly as x, the equation is of the form
y = kx, where k is constant of proportionality
Putting y = 12 and x = 4, we have
12 = k*4
k = 3
So. the required linear equation is y = 3x or y - 3x = 0
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y = kx, where k is constant of proportionality
Putting y = 12 and x = 4, we have
12 = k*4
k = 3
So. the required linear equation is y = 3x or y - 3x = 0
If it helped please mark as brainliest...
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