let y varies directly as x.if y=15 when x=5,then write a linear equation.
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The required linear equation is 3x - y = 0
Given:
y varies directly as x
y = 15 and x = 5
To find:
Write a linear equation
Solution:
Given y varies directly as x
⇒ y ∝ x
⇒ y = kx ---- (1) [ here k is an arbitrary constant ]
Given that y = 15 and x = 5
Substitute above values in equation (1)
15 = k5 ---- (1)
⇒ k = 15/5 = 3
⇒ k = 3
Now substitute k = 3 in (1)
⇒ y = 3x
⇒ 3x - y = 0
Therefore, required linear equation is 3x - y = 0
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