Question

LEVEL-1
1. Find the area of a quadrilateral ABCD is which AB = 3 cm, BC = 4 cm, CD = 4 cm,
DA = 5 cm and AC = 5 cm.
INCERT]​

Answer 1

Answer:

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Answer 2

Answer:

15.16.

Step-by-step explanation:

Area of the quadrilateral ABCD = Area of △ABC + Area of △ADC ….(1)

△ABC is a right-angled triangle which B.

Area of △ABC = 1/2 x Base x Height  = 1/2 x AB x BC = 1/2 x 3 x 4 = 6

Area of △ABC = 6 cm² ……(2)

Now, In △CAD,  Sides are given, apply Heron’s Formula.

$\sqrt{s(s-a)(s-b)(s-c)}$

s = a + b +c / 180

Where, a, b and c are sides of a triangle.

Perimeter = 2s = AC + CD + DA

2s = 5 cm + 4 cm + 5 cm  2s = 14 cm  s = 7 cm

$\sqrt{7*(7-5)(7-4)(7-5)}$

$\sqrt{7*2*3*2}$

$2\sqrt{21}$

= 9. 16 cm²

Area of the △CAD = 9.16 cm² …(3)  

Using equation (2) and (3) in (1), we get  

Area of quadrilateral ABCD = (6 + 9.16) cm²

= 15.16 cm².

∴Area of quadrilateral ABCD = 15.16 cm²