Question

lf 12 I of work done in moving 2 C of electric charge through a conductor. what is the P.D at the ends of the conductorएक्सल आईएफ ऊ वेयर इज डन इन मूविंग टू कॉलम्स आफ इलेक्ट्रिक चार्ज कंडक्टर व्हाट इज द पोटेंशियल डिफरेंस एंड द एंड ऑफ द कंडक्टर ​

Answer 1

Given :

Work done = 12 J

Magnitude of charge = 2 C

To Find :

Potential difference across the ends of conductor.

Solution :

❒ Work done in moving a charge of magnitude Q from one point (at 0 volt) to another point (at V volt) is given by

• W = Q × ∆V = Q × (V - 0) = QV

» W denotes work done

» Q denotes charge

» ∆V denotes pd

• Work done is a scalar quantity having only magnitude.
• SI unit : J

By substituting the given values;

$\sf:\implies\:Pd=\dfrac{Work\:done}{Charge}=\dfrac{W}{Q}$

$\sf:\implies\:Pd=\dfrac{12}{2}$

$\bf:\implies\:Pd=6\:V$

Knowledge BoosteR :

• Electric potential is a scalar quantity while potential gradient is a vector quantity.
• The electric potential near an isolated positive charge is positive and the electric potential near an isolated negative charge is negative.