lf A= {3, 6, 9, 12, 15, 18, 21} , B={4, 8, 12, 16, 20 }, C={2, 4, 6, 8, 10, 12, 14, 16} D={5, 10, 15, 20}; Find C - D
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concept :- A - B shows the relative complement of the set, which represents members of set A which are not part of set B. see figure , here shaded region is shown, this shaded region indicates A - B.
here, A= {3, 6, 9, 12, 15, 18, 21},
B={4, 8, 12, 16, 20 },
C={2, 4, 6, 8, 10, 12, 14, 16},
D={5, 10, 15, 20}.
so, C - D = {2, 4, 6, 8, 10, 12, 14, 16} - {5, 10, 15, 20}
here you can see that 10 is present in both sets so, C - D won't contain 20 and will contain rest elements of C.
hence, C - D = {2, 4, 6, 8, 12, 14, 16}
here, A= {3, 6, 9, 12, 15, 18, 21},
B={4, 8, 12, 16, 20 },
C={2, 4, 6, 8, 10, 12, 14, 16},
D={5, 10, 15, 20}.
so, C - D = {2, 4, 6, 8, 10, 12, 14, 16} - {5, 10, 15, 20}
here you can see that 10 is present in both sets so, C - D won't contain 20 and will contain rest elements of C.
hence, C - D = {2, 4, 6, 8, 12, 14, 16}
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Solution :
Given C = { 2,4,6,8,10,12,14,16 }
D = { 5,10,15,20 }
C-D = {x:x€C and x doesn't belongs to D}
= { 2,4,6,8,10,12,14,16 } - { 5,10,15,20 }
= { 2,4,6,8,12,14,16 }
••••
Given C = { 2,4,6,8,10,12,14,16 }
D = { 5,10,15,20 }
C-D = {x:x€C and x doesn't belongs to D}
= { 2,4,6,8,10,12,14,16 } - { 5,10,15,20 }
= { 2,4,6,8,12,14,16 }
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