Question

lf a-b=10 ab=11 find a+b ​

Answer 1

Answer:

(a-b)² = a²+b²-2ab

10²= a²+b²-2(11)

a²+b² = 100-22

a²+b² = 88

(a+b)² = a²+b²+2ab

(a+b)² = 88+2(11)

(a+b)² = 88+22

(a+b)² = 110

a+b = ✓110

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Answer 2

Answer:

a+b = 12

Step-by-step explanation:

$a-b = 10\\ab = 11\\(a-b)^2 = a^2+b^2-2ab \\10^2 = a^2 + b^2 - 2(11)\\100 + 22 = a^2+b^2\\a^2+b^2 = 122\\Now,\\( a+b )^2 = a^2 + b^2 + 2ab\\a+b = \sqrt{a^2 + b^2 + 2ab} \\a+b = \sqrt{122+2(11)}\\a+b = \sqrt{144}\\\\a+b = 12$