lf HCF of 171 & 95 is A and is
expressible in the form of 95 m+171 n
then the value of A+m+n are
respectively
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Given:
- HCF of 171 and 95 is A
- A can be expressed as 95m + 171n
To find: the value of A + m + n
Solution:
- 171 = 1 × 3 × 3 × 19
- 95 = 1 × 5 × 19
- So HCF of 171 and 95 is (1 × 19) = 19.
- Thus, A = 19.
We have: 171 = 95 × 1 + 76
95 = 76 × 1 + 19
76 = 19 × 4
Now, 95 = 76 × 1 + 19
or, 19 = 95 - 76 × 1
= 95 - (171 - 95 × 1) × 1
= 95 - 171 × 1 + 95 × 1
= 95 × 2 - 171 × 1 ... ...(1)
We have: 19 = 95m + 171 and comparing with (i), we get
- m = 2 and n = - 1
Now, A + m + n = 19 + 2 - 1 = 20
Answer: A + m + n = 20
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