lf linear momentum of a body increases by x%.then the increase in the kinetic energy of the body will be?
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Momentum= m*v
and KE= 1/2*m*v*v
Change in momentum will be due to change in velocity of a body
if momentum= 75/100=1/4
than Ke= 75/100*v*1/2= 1/8v
leelah:
but the options varry there is no answer like this
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Suppose the original momentum of the body to be ‘p’ and a 50% increase leads to amomentum of p+(50/100)p=1.5p
The relation between momentum ‘p’ and kinetic energy ‘k’ is p^2=2km (m is mass of object) hence k=(p^2)/2m
New kinetc energy
k' = ((1.5p)^2)/2m ( as new p is 1.5p)
k'=2.25*((p^2)/2m) =2.25*k
So, kinetic energy increased by 125%
The relation between momentum ‘p’ and kinetic energy ‘k’ is p^2=2km (m is mass of object) hence k=(p^2)/2m
New kinetc energy
k' = ((1.5p)^2)/2m ( as new p is 1.5p)
k'=2.25*((p^2)/2m) =2.25*k
So, kinetic energy increased by 125%
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