lf sinA3= cos(26-
A) where 3A is an acute angle, find the value of A
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sin =cos(90-tita)
cos (90-A3)=cos(26-A)
90-A3=26-A
90-26=3A-A
64=2A
A =32
cos (90-A3)=cos(26-A)
90-A3=26-A
90-26=3A-A
64=2A
A =32
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