Question

lf the deviation if a light ray 0° when incident on a mirror then angle of incidence is​

Answer 1

Required Answer:-

Angle of deviation is given by 180 - (Angle of incidence + Angle of reflection). And we know that, Angle of incidence = Angle of reflection according to laws of reflection.

Let,

Angle of incidence = Angle of reflection = Θ

Then, Angle of deviation will be 180° - 2Θ, as extended incident ray is perceived by our brain. If angle of deviation is 0°. Then,

➙ 180° - 2Θ = 0°

➙ 2Θ = 180°

➙ Θ = 90°

Hence,

Angle of incidence and Angle of reflection will be 90°. Your answer is 90°. The ray is passing straight as the mirror. Hence, no deviation $.$

Answer 2

Explanation:

Required Answer:-

Angle of deviation is given by 180 - (Angle of incidence + Angle of reflection). And we know that, Angle of incidence = Angle of reflection according to laws of reflection.

Let,

Angle of incidence = Angle of reflection = Θ

Then, Angle of deviation will be 180° - 2Θ, as extended incident ray is perceived by our brain. If angle of deviation is 0°. Then,

➙ 180° - 2Θ = 0°

➙ 2Θ = 180°

➙ Θ = 90°

Hence,

Angle of incidence and Angle of reflection will be 90°. Your answer is 90°. The ray is passing straight as the mirror. Hence, no deviation ..