lf the sum of two number is divided by 15 the quatient is 2 and remainder is 10 lf the difference of same number is divided by 3 then the quatient is 4 and remainder is 2 find the number
Answers
Answered by
1
Answer:
27,13
Step-by-step explanation:
Let the numbers be x and y.
We know that Dividend = Divisor × Quotient + Remainder
As per the statement, "If the sum of two numbers is divided by 15, the quotient is 2 and the remainder is 10 , we get x+y=15×2+10=>x+y=40 --- (1)
Also, as the difference of the same numbers is divided by 3
then the quotient is 4 and the remainder is 2, we get x−y=3×4+2=>x−y=14 --- (2)
Adding equations 1 and 2, we get 2x=54=>x=27
Substituting
x=27 in the equation (1), we get 27+y=40=>y=13
Thus the numbers are 27,13
Answered by
0
(X+y)/15= 40/15
X+y=40
(X-y)/3= 14/3
X-y=14
Adding
2x= 54
X= 27
AndY = 13
X+y=40
(X-y)/3= 14/3
X-y=14
Adding
2x= 54
X= 27
AndY = 13
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